9x^2+61x-180=0

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Solution for 9x^2+61x-180=0 equation:



9x^2+61x-180=0
a = 9; b = 61; c = -180;
Δ = b2-4ac
Δ = 612-4·9·(-180)
Δ = 10201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10201}=101$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-101}{2*9}=\frac{-162}{18} =-9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+101}{2*9}=\frac{40}{18} =2+2/9 $

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